f^2=3.333337

Solution for f^2=3.333337 equation:

f^2=3.333337

We move all terms to the left:

f^2-(3.333337)=0

We add all the numbers together, and all the variables

f^2-3.333337=0

a = 1; b = 0; c = -3.333337;
Δ = b2-4ac
Δ = 02-4·1·(-3.333337)
Δ = 13.333348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{13.333348}}{2*1}=\frac{0-\sqrt{13.333348}}{2}
=-\frac{\sqrt{}}{2}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{13.333348}}{2*1}=\frac{0+\sqrt{13.333348}}{2}
=\frac{\sqrt{}}{2}
$